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7x+4.9x^2-950=0
a = 4.9; b = 7; c = -950;
Δ = b2-4ac
Δ = 72-4·4.9·(-950)
Δ = 18669
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18669}=\sqrt{49*381}=\sqrt{49}*\sqrt{381}=7\sqrt{381}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7\sqrt{381}}{2*4.9}=\frac{-7-7\sqrt{381}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7\sqrt{381}}{2*4.9}=\frac{-7+7\sqrt{381}}{9.8} $
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